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The proof is done using the standard form of a quadratic equation and solving the standard form by completing the square Start with the the standard form of a quadratic equation ax 2 bx c = 0 Divide both sides of the equation by a so that you can complete the squareTherefore (6), with a and b interchanged, is identical to (4) Thus since (m 2n 2, 2 ⁢ m ⁢ n, m 2 n 2), as in (4), is a primitive Pythagorean triple, we can say that (a, b, c) is a primitive pythagorean triple if and only if there exists relatively prime, positive integers m and n, m > n, such that a = m 2n 2, b = 2 ⁢ m ⁢ n, andThis is how I see it Using Distance Formula Show That The Points A 3 1 B 6 4 And C 8 6 Are Collinear Brainly In What is formula of (a+b+c)3

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